LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
in General by (54.3k points)
closed by
A 500-watt carrier is modulated to a depth of 80%. Calculate the total power in the modulated wave.
1. 512.5 W
2. 500 W
3.  450 W
4. 660 W

1 Answer

0 votes
by (30.0k points)
selected by
Best answer
Correct Answer - Option 4 : 660 W


The total transmitted power for an AM system is given by:

\({P_t} = {P_c}\left( {1 + \frac{{{μ^2}}}{2}} \right)\)

Pc = Carrier Power

μ = Modulation Index


With PC = 500 W and μ = 0.80, the total power in the modulated wave will be:

\({P_t} = {500}\left( {1 + \frac{{{(0.8)^2}}}{2}} \right)\)

Pt = 660 W

NoteThe transmitted power is independent of the modulation index in the case of FM and PM.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.