Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
45 views
in General by (114k points)
closed by
A perfect gas at 27°C is heated at constant pressure till its volume is double. The final temperature is
1. 54°C
2. 108°C
3. 327°C
4. 600°C
5. 800° C

1 Answer

0 votes
by (115k points)
selected by
 
Best answer
Correct Answer - Option 3 : 327°C

Concept:

As the gas is heated at constant pressure, so by applying Charles’s law

\(\frac{{{V_2}}}{{{V_1}}} = \frac{{{T_2}}}{{{T_1}}}\)

Calculation:

Given:

T1 = 27°C = 300 K, V1 = V, V2 = 2V

Therefore, \(2= \frac{{{T_2}}}{{300}} \)

T2 = 600 K = 600 - 273 = 327°C

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...