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Find the value of \(\rm \int_{-\pi }^{\pi }sinx \ dx\)
1. 1
2. 0
3. 2
4. 3

1 Answer

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Best answer
Correct Answer - Option 2 : 0

Concept:

The function f(x) is an odd function if f(x) = - f(-x) and an even function if f(x) = f(-x).

  • When f(x) is an even function then \(\rm \int_{-a}^{a}f(x)dx=2\int_{0}^{a}f(x)dx\)
  • When f(x) is odd function then \(\rm \int_{-a}^{a}f(x)dx=0\)

Calculation:

Given: \(\rm \int_{-\pi }^{\pi }sinx \ dx\)

Let f(x) = sin x

As we know that, f(- x) = sin (- x) = - sin x = - f(x).

So, sin x is an odd function.

As we know that when f(x) is an odd function then \(\rm \int_{-a}^{a}f(x)dx=0\)

 \(\Rightarrow\rm \int_{-\pi }^{\pi }sinx \ dx=0\) 

Hence, the correct option is 2.

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