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X, Y and Z invested money for certain time period in the ratio of 10 15 12. Y invested Rs. 15,000 more than the money invested by X while X invested Rs. 20,000 less than the money invested by Z. X and Y invested money for 5 and 3 years respectively. Find the time period for which Z invested the money.
1. 3 years
2. 4 years
3. 5 years
4. 2 years

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Correct Answer - Option 4 : 2 years

Given:

X, Y and Z invested money for certain time period in the ratio of 10 ∶ 15 ∶ 12.

Y invested Rs. 15,000 more than the money invested by X while X invested Rs. 20,000 less than the money invested by Z.

X and Y invested money for 5 and 3 years respectively.

Concepts used:

Net capital invested = Time for which capital is invested × capital invested

Calculation:

Y invested Rs. 15,000 more than the money invested by X while X invested Rs. 20,000 less than the money invested by Z.

Let the money invested by Z be x.

⇒ Money invested by X = x – 20,000

⇒ Money invested by Y = x – 20,000 + 15,000 = x – 5,000

X and Y invested money for 5 and 3 years respectively.

⇒ Net capital invested by X = 5 × (x – 20,000) = 5x – 1,00,000

⇒ Net capital invested by Y = 3 × (x – 5,000) = 3x – 15,000

Let Z invested capital for y years.

Net capital invested by Z = y × x = xy

Ratio of capital of X, Y and Z = (5x – 1,00,000) ∶ (3x – 15,000) ∶ xy

⇒ 10 ∶ 15 ∶ 12 = (5x – 1,00,000) ∶ (3x – 15,000) ∶ xy

On comparing,

⇒ 10/15 = (5x – 1,00,000)/(3x – 15,000)

⇒ 2 × (3x – 15,000) = 3 × (5x – 1,00,000)

⇒ 6x – 30,000 = 15x – 3,00,000

⇒ 9x = 2,70,000

⇒ x = Rs. 30,000

15/12 = (3x – 15,000)/xy

⇒ 5/4 = (3 × 30,000 – 15,000)/(30000y)

⇒ 5/4 = 75000/30000y

⇒ 5/4 = 5/2y

⇒ y = 2 

Z invested money for 2 years.

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