Correct Answer - Option 1 : zero
Calculation:
We have,
⇒ \(a_n = \frac{1.2.3...n}{n.n.n...n}\)
⇒ \(a_n=(\frac{1}{n})(\frac{2}{n})(\frac{3}{n})...(\frac{n}{n})<\frac{1}{n}\)
Thus, 0 < an < 1/n
Taking limit as n-->∞, we have
⇒ 0 ≤ \(\mathop {\lim }\limits_{n \to \infty } a_n\) ≤ \(\mathop {\lim }\limits_{n \to \infty } (\frac{1}{n})\) = 0
Therefore, \(\mathop {\lim }\limits_{n \to \infty } a_n\) = 0
Hence the sequence converges to zero.