Correct Answer - Option 2 : 1/13
Concept:
tan(A - B) = \(\rm \frac{tan A-tanB}{1+tanAtanB}\)
Calculation:
Here, tan(α + β) = 4, and tan(α - β) = 3
∴ tan [(α + β) - (α - β)] = \(\rm \frac{tan (\alpha+β) -tan (\alpha+β) }{1+tan (\alpha+β) tan (\alpha-β) }\)
⇒ tan (2β) = \(\frac{4-3}{1+(4)(3)}\)
= 1/13
Hence, option (2) is correct.