Correct Answer - Option 1 : tan
-1 x + c
Concept:
\(\smallint \frac{1}{{{x^2} + 1}} = {\tan ^{ - 1}}x + c\;\)
Calculation:
\(\smallint \frac{{{x^2} - 1}}{{{x^4} - 1}}dx\)
\(= \smallint \frac{{{x^2} - 1}}{{\left( {{x^2} - 1} \right)\left( {{x^2} + 1} \right)}}dx\)
\(= \smallint \frac{1}{{{x^2} + 1}}dx\)
= tan-1 x + c