Correct Answer  Option 3 : All the above
CONCEPT:
 The kinetic energy of the electron in an orbit is given by
\(⇒ KE = \frac{1}{2}mV^{2} = \frac{1}{2} m \times \frac{e ^{2}}{4\pi \epsilon_{0}mr} =\frac{e^{2}}{8\pi\epsilon_{0}mr}\)
 The potential energy of an electron in an orbit is given by
\(⇒ U = \frac{e^{2}}{4\pi\epsilon_{0}r}\)
 The total energy of the electron is given by
⇒ T = KE + U
\(⇒ T = \frac{e^{2}}{8\pi\epsilon_{0}r}  \frac{e^{2}}{4\pi\epsilon_{0}r} = \frac{e^{2}}{8\pi \epsilon_{0}r}\)
Where e= charge, r = orbital radius, T = Total energy
EXPLANATION:
 The total energy of an electron in an atom is given by
\(⇒ T = \frac{e^{2}}{8\pi \epsilon_{0}r}\)
 By analyzing the above equation it is clear that the total energy is inversely proportional to the distance, which in turn means that
 As the value of r changes the value of T changes, which justifies statement 4
 As the value of r increases the value of T increases, which justifies statement 3. [ Kindly note the negative sign in the equation of T, \(T = \frac{e^{2}}{8\pi \epsilon_{0}r}\)]

By giving an amount of energy that equal to the energy of an electron in an atom the electron can be released from it.
 Since the energy of an electron in an atom is \( T = \frac{e^{2}}{8\pi \epsilon_{0}r}\)if we gave energy \( E = +\frac{e^{2}}{8\pi\epsilon_{0}r}\)then the electron can be released from the atom. Hence, statement 2 is correct
 The energy of an electron in an atom is \(T = \frac{e^{2}}{8\pi \epsilon_{0}r}\) , by analyzing the equation means the electron is having negative energy, which in turn means the electron can't escape from the atom. Hence, statement 1 is correct
 The option which states all the statement is correct is the answer, Hence, option 3 is the answer
 Options 1, 2, and 3 doesn't contain all the statements. Hence these options are incorrect