Correct Answer  Option 1 : 20 pF
CONCEPT:

Capacitance: The ability of an electric system to store the electric charge is known as capacitance.
C = Q/V
where Q is the charge on it, V is the voltage, and C is the capacitance of it.
For the parallel plate capacitor, the capacitance is given by:
\(C= \frac{KA\varepsilon _{0}}{d}\)
where A is the area of the plate, d is the distance between plates, K is the dielectric constant of material and ϵ_{0} is constant.
CALCULATION:
Given that:
Dimensions of plate = area (A) = 2 cm × 3 cm = 6 cm^{2} = 6 × 10^{4} cm^{2}
Distance between plates (d) = 1 mm = 1 × 10^{3} m
Dielectric constant of paper (K) = 3.7
ϵ0 = 8.85 × 1012 C2 N1 m2
For the parallel plate capacitor, the capacitance is given by:
\(C= \frac{KA\varepsilon _{0}}{d}\)
\(C= \frac{3.7× 6× 10^{4} ×8.85 × 10^{12}}{1 × 10^{3}}\)
C = 2 × 10^{11} F = 20 pico farad
Capacitance (C) = 20 pF
Hence option 1 is correct.