Correct Answer - Option 1 : 1 : 1 : 1
Given
a + b + c = 8√3
a2 + b2 + c2 = 64
Concept
a2 + b2 + c2 = ab + bc + ca
Then, a = b = c
(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca)
Calculation
(8√3)2 = 64 + 2(ab + bc + ca)
⇒ 192 - 64 = 2(ab + bc + ca)
⇒ 128/2 = ab + bc + ca
⇒ 64 = ab + bc + ca
As a2 + b2 + c2 = ab + bc + ca
So, a = b = c
b × b = ca
⇒ b2 = ca
Similarly, ab = b2 and bc = b2
64 = b2 + b2 + b2
64 = 3b2
64/3 = b2
8/√3 = b
a = b = c = 8/√3
⇒ 1 : 1 : 1
∴ a ∶ b ∶ c is 1 ∶ 1 ∶ 1