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The ratio of modulus of rigidity to young’s modulus is 0.40. What will be the Poisson’s ratio?
1. 0.55
2. 0.45
3. 0.25
4. 0.35

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Correct Answer - Option 3 : 0.25

Concept:

Relation between modulus of rigidity (G), young’s modulus (E) & Poisson’s ratio (μ) is

E=2G(1+μ)

Calculation:

Given:

\(\frac {{G}}{{E}} \) = 0.4

E = 2G (1 + μ)

\(\frac {{E}}{{G}} \) = 2 (1 + μ)

\(\frac {{1}}{{0.4}} \) = 2 (1 + μ)

1.25 = 1 + μ 

μ = 0.25  

Other relations between elastic constants

E = \( \frac {{9KG}}{{3K+G}}\)

E = 3K (1 - 2μ)

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