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Average age of a father and his two sons is 32 years. Four years ago, the average age of the two sons was 17 years. If the difference between the ages of two sons is 4 years, then find the present age of father. 
1. 40
2. 54
3. 46
4. 42

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Correct Answer - Option 2 : 54

Given:

The average age of the father and his two sons is 32 years.

Four years ago, the average age of the two sons is 17 years.

The difference between the ages of two sons is 4 years

Formula Used:

Average = Sum of given observation/Number of observations

Calculation:

Four years ago the average age of two sons is 17 years

Present average age of two sons = 17 + 4 = 21 years

⇒ Sum of present ages of two sons = 21 × 2 = 42 years

The average age of the father and his two sons = 32 years

⇒ Sum of ages of father and his two sons = 32 × 3 = 96 years

⇒ Father’s age = (Sum of ages of father and his two sons) – (Sum of ages of two sons)

⇒ Father’s age = (96 – 42) years

⇒ Father’s age = 54 years

The present age of the father is 54 years.

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