LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
11 views
in Physics by (54.3k points)
closed by
If V1 and V2 are the initial and final volume respectively, then which of the following is an expression for the work done in an iso-thermal process:
1. \(\mu RTlog_e\left ( \frac{V_1}{V_2} \right )\)
2. \(\mu RTlog_e\left ( \frac{V_2}{V_1} \right )\)
3. \(\mu RTlog_e\left ( {V_1}-{V_2} \right )\)
4. \(\mu RTlog_e\left ( {V_2}-{V_1} \right )\)

1 Answer

0 votes
by (30.0k points)
selected by
 
Best answer
Correct Answer - Option 2 : \(\mu RTlog_e\left ( \frac{V_2}{V_1} \right )\)

CONCEPT:

Isothermal process:

  • When a thermodynamic system undergoes a physical change in such a way that its temperature remains constant, then the change is known as the isothermal process.

⇒ T = constant

EXPLANATION:

  • We know that the work done in an isothermal process is given as,

\(\Rightarrow W=\mu RTlog_e\left ( \frac{V_2}{V_1} \right )\)

  • Hence, option 2 is correct.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...