Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
237 views
in Physics by (114k points)
closed by
If the increase in internal energy of the system is 100 J, when 200 J heat is given to the system, then the work done will be:
1. 200 J
2. 300 J
3. 100 J
4. 0 J

1 Answer

0 votes
by (115k points)
selected by
 
Best answer
Correct Answer - Option 3 : 100 J

Concept:

The first law of thermodynamics

This law states that the total heat given or taken out of the system will always be equal to the work done and change in the internal energy of the system.

​⇒ Q = W + ΔU

Where Q = heat, W = work done, and ΔU = change in internal energy

Calculation:

Given Q = 200 J, and ΔU = 100 J

By the first law of thermodynamics,

​⇒ Q = W + ΔU

​⇒ W = Q - ΔU

​⇒ W = 200 - 100

​⇒ W = 100 J

Hence, option 3 is correct.

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...