Correct Answer - Option 2 : (1/√2) times
de Broglie wavelength of electrons: Louis de Broglie theorized that not only light possesses both wave and particle properties, but rather particles with mass - such as electrons - do as well.
- The wavelength of material waves is also known as the de Broglie wavelength.
de Broglie wavelength (λ) of electrons can be calculated from Planks constant h divided by the momentum of the particle.
λ = h/p
where λ is de Broglie wavelength, h is Plank's const, and p is the momentum.
- In terms of Energy, de Broglie wavelength of electrons:
where λ is de Broglie wavelength, h is Plank's const, m is the mass of an electron, and E is the energy of the electron.
Given that E2 = 2E1
So the correct answer is option 2.