# There are 5 purple balls and 7 orange balls. Two balls are selected one by one without replacement. Find the probability that first in purple and seco

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There are 5 purple balls and 7 orange balls. Two balls are selected one by one without replacement. Find the probability that first in purple and second is orange.
1. 25/132
2. 17/132
3. 15/132
4. 35/132
5. 19/132

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Correct Answer - Option 4 : 35/132

Given:

There are 5 purple balls and 7 orange balls.

Formula Used:

Probability = Number of observation/Total number of observation

Calculation:

The number of purple balls is 5.

The number of orange balls is 7.

The total number of balls in the box = 5 + 7 = 12

The probability of getting purple ball = 5/12

The remaining ball = 12 - 1 = 11

The probability of getting orange ball = 7/11

The probability of getting first in purple and second is orange = 5/12 × 7/11 = 35/132

∴ The probability of getting first in purple and second is orange is 35/132.