LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
11 views
in Aptitude by (54.3k points)
closed by
Kiran creating an alcohol solution by mixing two different alcohol solutions of 15% and 20% respectively. If the resulting mixture has 18% alcohol content, what is the ratio of the volume of alcohol solutions used?
1. 1 : 3
2.  2 : 3
3. 5 : 2
4. 2 : 1

1 Answer

0 votes
by (30.0k points)
selected by
 
Best answer
Correct Answer - Option 2 :  2 : 3

Calculation:

Let volume of alcohol solutions are Vand  Vrespectively.

⇒ Volume of alcohol in the resulting mixture = 15% of V+ 20% of V2

⇒ ((15/100) × V1) + ((20/100) × V2)

⇒ (15V1+ 20V)/100

which is also equal to 18% of (V+ V2).

⇒ (15V1+ 20V)/100 = (18 × (V+ V2))/100

2V= 3V1

The ratio of volume is 2 : 3 .

If a mixture of Q1 quantity C1% content is mixing with Q2 quantity C2% mixture, and the concentration of the new mixture is Cnew% , then the following equation can be used

C1% of Q1 + C2% of Q2 = Cnew% of (Q1 + Q2)

⇒ C1Q1 + C2Q2 = Cnew(Q1 + Q2)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...