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The income of x is 80% more than of y, and the income of z is 60% of the total income of x and y. By how much percentage the income of z is less than the income of x  (correct to one decimal place)?
1. 6.3%
2. 7.1%
3. 7.3%
4. 6.7%

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Correct Answer - Option 4 : 6.7%

Given:

Income of x = 80% more than of y

Income of z = 60% of the total income of x and y

Concept used:

Percentage of income of z is less than income of x,

⇒ [(x – z)/x] × 100

Calculation:

Let the income of y be 100 and income of x be 180 respectively(80% more than y).

And the income of z is 168 that is 60% of the total income of x and y

Percentage of income of z is less than income of x,

⇒ [(180 - 168)/180] × 100

⇒ [12/180] × 100

⇒ 6.7%

∴ Income of z is 6.7% less than the income of x .

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