Correct Answer - Option 2 : 12/x
Concept:
\(\rm \frac{\mathrm{d} (logx)}{\mathrm{d} x} = \frac{1}{x}\)
log xa = a log x
Calculation:
Given: f(x) = 4log x3 = 12log x
Now, f'(x) = \(\rm \frac{\mathrm{d} (12\log x)}{\mathrm{d} x}\)
= \(12\frac{\mathrm{d} (\log x)}{\mathrm{d} x}\)
= 12/x
∴ The required value is 12/x.