Correct Answer - Option 3 : 82 mm
Concept:
The mean radius of friction face assuming the uniform pressure condition is given by:
\({R_m} =\frac{2}{3}\left( {\frac{{r_o^3\; - \;r_i^3}}{{r_o^2\; - \;r_i^2}}} \right)\)
Where ro & ri are the external and internal radii of the clutch.
Calculation:
Given:
ro = 100 mm, ri = 60 mm.
\({R_m} =\frac{2}{3}\left( {\frac{{r_o^3\; - \;r_i^3}}{{r_o^2\; - \;r_i^2}}} \right)\)
\({R_m} =\frac{2}{3}\left( {\frac{{100^3\; - \;60^3}}{{100^2\; - \;60^2}}} \right) = 81.67\; mm\) ≈ 82 mm
∴ The mean radius of the friction face assuming the uniform pressure condition is 82 mm.