Correct Answer - Option 1 : 5 kW
Concept:
Power transmitted by a belt:
P = (Tt – Ts) × V
where Tt the tension on the tight side (N), Ts is the tension on the slack side (N), V is the velocity of the belt in m/s.
Calculation:
Given:
Tt = 2000 N, Ts = 1000 N, V = 5 m/s
P = (Tt – Ts) × V
P = (2000 - 1000) × 5 = 5000 Nm/s = 5 kW
∴ The power transmitted in the belt drive is 5 kW.