Correct Answer - Option 3 : 25 MPa
Concept:
\(Stress\;(\sigma) = \frac{Load}{Area\; of\; cross\; section }\)
Here, the Area of the cross-section is perpendicular to the applied load.
Calculation:
Given:
Load = 100 N, Area of rectangular plate = 4 mm2.
\(Stress\;(\sigma) = \frac{Load}{Area\; of\; cross\; section }\)
\(\sigma = \frac{100}{4}\) = 25 N/mm2 or MPa
∴ The stress developed in the plate is 25 MPa