LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
29 views
in Trigonometry by (54.3k points)
closed by
Find the value of cos(2010°)
1. \(-\frac{\sqrt3}{2}\)
2. \(-\frac{1}{2}\)
3. \(-\frac{1}{\sqrt2}\)
4. \(\frac{1}{2}\)

1 Answer

0 votes
by (30.0k points)
selected by
 
Best answer
Correct Answer - Option 1 : \(-\frac{\sqrt3}{2}\)

Concept:

cos (2nπ ± θ) = cos θ

cos (90 + θ) = -sin θ

 

Calculation:

Here,  cos(2010°)

⇒ cos (6 × 360° - 150°)

= cos(150°)            (∵ cos (2nπ ± θ) = cos θ)

= cos(90° + 60°)

= - sin(60°)            (∵ cos (90 + θ) = -sin θ)

\(-\frac{\sqrt3}{2}\)

Hence, option (1) is correct.

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...