Correct Answer - Option 3 :

B and C
**Given: **

SP1 = Rs. m

SP2 = 80% of m

Loss = 12%

**Formula Used: **

Profit% = (Profit /CP) × 100

SP = {(100 + P%)/100} × CP

SP = {(100 – L%)/100} × CP

Where P → Profit, L → loss, CP → cost price and SP → selling price.

**Calculation:**

SP2 = 80% of m

⇒ (80/100) × m

Loss = 12%

⇒ SP2 = {(100 – 12)/100} × CP

⇒ (80/100) × m = {(100 – 12)/100} × CP

⇒ 80m = 88CP

⇒ 10m = 11CP

⇒ m = (11/10) × CP

⇒ m = (110/100) × CP

⇒ m = {(100 + 10)/100} × CP

⇒ **m is 10% more than CP**

A. m is 10% less than the CP

m is 10% more than CP

⇒ A is incorrect

B. If cost price is 550, original selling price is Rs. 605

Original selling price = m

⇒ m = 110% of CP

⇒ (110/100) × 550

⇒ 605

⇒ B is correct

C. If cost price is 550, 80% of m = 484

m = 110% of CP

⇒ 80% of m = 80% of 110% of CP

⇒ (80/100) × 605

⇒ 484

⇒ C is correct

D. 88% of CP = m

⇒ m = 110% of CP

⇒ D is incorrect

**∴ ****B and C are correct.**