Correct Answer - Option 1 : 30

**Concept:**

The bearing characteristic number is calculated by,

**\(\frac{{μ N_s}}{P}=\rm Bearing~characteristic~number\)**

Where, μ = absolute viscosity of lubricant (kg/m.s), N = speed of the journal (rps), P = bearing pressure (N/mm^{2})

**Calculation:**

**Given:**

μ = 1.2 kg-m/s, N = 1500 r.p.m, P = 1 N/m2

**\(\rm Bearing~characteristic~number=\frac{{μ N_s}}{P}\;\)**

**\(= \frac{1.2\times1500}{60\times1} = 30\;\)**

**The bearing characteristics number is 30.**