Correct Answer - Option 1 : 30
Concept:
The bearing characteristic number is calculated by,
\(\frac{{μ N_s}}{P}=\rm Bearing~characteristic~number\)
Where, μ = absolute viscosity of lubricant (kg/m.s), N = speed of the journal (rps), P = bearing pressure (N/mm2)
Calculation:
Given:
μ = 1.2 kg-m/s, N = 1500 r.p.m, P = 1 N/m2
\(\rm Bearing~characteristic~number=\frac{{μ N_s}}{P}\;\)
\(= \frac{1.2\times1500}{60\times1} = 30\;\)
The bearing characteristics number is 30.