Correct Answer - Option 3 : 100 kN-m

__Concept:__

The maximum fluctuation of the energy during operation is given by:

ΔE = Work done per cycle × C_{E}

Work done per cycle = \(P×\frac{60}{N}\)

where C_{E} = Coefficient of fluctuation of energy, P = Power, N = Speed in r.p.m

__Given:__

__Calculation:__

P = 600 kW, N = 180 r.p.m, CE = 0.5

Work done per cycle = \(P\;×\;\frac{60}{N}\) = \(600\;×\;\frac{60}{180}\) = 200 × 10^{3 }Nm.

ΔE = Work done per cycle × CE

ΔE = 200 × 10^{3} × 0.5 = **100 kN-m.**