Correct Answer - Option 3 : 100 kN-m
Concept:
The maximum fluctuation of the energy during operation is given by:
ΔE = Work done per cycle × CE
Work done per cycle = \(P×\frac{60}{N}\)
where CE = Coefficient of fluctuation of energy, P = Power, N = Speed in r.p.m
Given:
Calculation:
P = 600 kW, N = 180 r.p.m, CE = 0.5
Work done per cycle = \(P\;×\;\frac{60}{N}\) = \(600\;×\;\frac{60}{180}\) = 200 × 103 Nm.
ΔE = Work done per cycle × CE
ΔE = 200 × 103 × 0.5 = 100 kN-m.