Correct Answer - Option 3 : 400 N/m
2
Concept:
The bulk modulus of elasticity of the liquid is given by
\(K = - \frac{{{{\Delta }}P}}{{\left( {\frac{{{{\Delta }}V}}{V}} \right)}}\;\)
Calculation:
Given:
V1 = 0.02 m3, P1 = 200 , V2 = 0.01 m3, P2 = 400 N/m2
\(K = - \frac{{{{\Delta }}P}}{{\left( {\frac{{{{\Delta }}V}}{V}} \right)}}\ =- \frac{P_2-P_1}{\frac{V_2-V_1}{V_1}}=-\frac{400-200}{\frac{0.01-0.02}{0.02}}= 400\; N/m^2 \)
The bulk modulus of elasticity of the liquid is 400 N/m2.