Correct Answer - Option 3 : 400 N/m

^{2}
__Concept:__

The bulk modulus of elasticity of the liquid is given by

\(K = - \frac{{{{\Delta }}P}}{{\left( {\frac{{{{\Delta }}V}}{V}} \right)}}\;\)

**Calculation:**

**Given:**

V_{1} = 0.02 m^{3}, P_{1} = 200 , V_{2} = 0.01 m^{3}, P_{2} = 400 N/m^{2}

\(K = - \frac{{{{\Delta }}P}}{{\left( {\frac{{{{\Delta }}V}}{V}} \right)}}\ =- \frac{P_2-P_1}{\frac{V_2-V_1}{V_1}}=-\frac{400-200}{\frac{0.01-0.02}{0.02}}= 400\; N/m^2 \)

**The bulk modulus of elasticity of the liquid is 400 N/m**^{2}.