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Find the last two digit of 1792 × 499 × 98.
1. 81
2. 82
3. 83
4. 84

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Correct Answer - Option 4 : 84

Given:

The number is 1792 × 499 × 98

Concept used:

Here we are going to divide each number by 100 and then add their reminder.

Calculation:

(1792 × 499 × 98)/100

When we divide 1792 by 100 we get (-8) as reminder, similarly with (-1) and (-2) with 499 and 98 respectively.

Sum of reminders: -8 × (-1) × (-2) = (-16)

The last two digits are 100 + (-11) = 100 – 16 = 84

∴ The last two digit of 1792 × 499 × 98 is 84.

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