Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
73 views
in Circles by (114k points)
closed by
Find radius of the circle x2+ y2+ 4x- 6y+ 11 = 0 
1. \(\rm\sqrt{6}\) units
2. \(\rm3\sqrt{2}\) units
3. \(\rm2\sqrt{6}\) units
4. \(\rm\sqrt{2}\) units

1 Answer

0 votes
by (115k points)
selected by
 
Best answer
Correct Answer - Option 4 : \(\rm\sqrt{2}\) units

Concept: 

General form of the equation of a circle, x2 + y2 + 2gx + 2fy + c = 0 

Radius = \(\rm\sqrt{g^{2}+f^{2}-c}\) 

Calculation: 

The given equation of circle is x+ y+ 4x - 6y + 11 = 0 

On compare with standard equation of circle x2 + y2 + 2gx + 2fy + c = 0  

We get ,  g = 2 , f = 3 and c = 11 

We know that , radius = \(\rm\sqrt{g^{2}+f^{2}-c}\) 

radius = \(\rm\sqrt{2^{2}+3^{2}-11}\)

 ⇒ radius = \(\rm\sqrt{2}\) units. 

The correct option is 4.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...