Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
125 views
in General by (114k points)
closed by

An oil of viscosity 0.5 N s/m2 and relative density 0.6 is flowing through a circular pipe of diameter 40 cm and of length 500 m. The average velocity of the oil is 2 m/s. Determine the pressure drop in a length of 500 m.


1. 200 kN/m2
2. 100 kN/m2
3. 250 kN/m2
4. 150 kN/m2

1 Answer

0 votes
by (115k points)
selected by
 
Best answer
Correct Answer - Option 2 : 100 kN/m2

Concept:
The pressure drop per unit length in a fully developed laminar flow through a pipe is given as,

\(\Delta P = \frac{{32μ {V_{mean}{L}}}}{{{D^2}}}\)

Where, μ = Viscosity of the fluid, Vmean = Mean velocity of flow, L = Length of pipe, D = Diameter of pipe

Calculation:

Given:

μ = 0.5 N s/m2 ,D = 40 cm = 0.4 m, Vmean = 2 m/s, L = 500 m

\(\Delta P = \frac{{32μ {V_{mean}{L}}}}{{{D^2}}} \)

\(\Delta P= \frac{{32\times0.5 \times{2\times{500}}}}{{{0.4^2}}} = 100\; kN/m^2\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...