Correct Answer - Option 2 : 100 kN/m
2
Concept:
The pressure drop per unit length in a fully developed laminar flow through a pipe is given as,
\(\Delta P = \frac{{32μ {V_{mean}{L}}}}{{{D^2}}}\)
Where, μ = Viscosity of the fluid, Vmean = Mean velocity of flow, L = Length of pipe, D = Diameter of pipe
Calculation:
Given:
μ = 0.5 N s/m2 ,D = 40 cm = 0.4 m, Vmean = 2 m/s, L = 500 m
\(\Delta P = \frac{{32μ {V_{mean}{L}}}}{{{D^2}}} \)
\(\Delta P= \frac{{32\times0.5 \times{2\times{500}}}}{{{0.4^2}}} = 100\; kN/m^2\)