Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
55 views
in General by (114k points)
closed by
If it is known that the decay constant of radium is 1.3566 ×  10-11 s-1 then find its half-life. (Given atomic mass of radium is 226.095 amu)
1. 1000 year
2. 1620 year
3. 1785 year
4. 1467 year

1 Answer

0 votes
by (115k points)
selected by
 
Best answer
Correct Answer - Option 2 : 1620 year

Concept:

Decay constant:
The time required for half of the original population of radioactive atoms to decay is called the half-life.

The relationship between the half-life, T1/2, and the decay constant is given by,

\(T_{1/2}=\frac{0.693}{λ}\)

Calculation:

Given,

λ = 1.3566 ×  10-11 s-1

From the above concept,

\(T_{1/2}=\frac{0.693}{λ}=\frac{0.693}{1.3566\times 10^{-11}}=5.1083\times10^{10}\ sec\)

Conversing second into the year,

\(5.1083\times10^{10}\ sec=\frac{5.1083\times10^{10}}{365\times24\times3600}=1620\ year\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...