Question

Two letters are chosen at random from the word ‘ASSASSINATION’. What is the probability that both the letters are vowels?

1. 11/13
2. 5/26
3. 6/13
4. 8/13
5. 10/13

Answer 1

Correct Answer - Option 2 : 5/26

Given:

Number of letters chosen = 2

Given word = ‘ASSASSINATION’

Formula used:

Combination formula = ⁿC_r = n!/(n - r)! r!

Calculation:

Total number of letters in the word = 13

Number of ways to choose 2 letters = ¹³C₂ = 78

Total number of vowels in the word = 6

Number of ways to choose 2 vowels = ⁶C₂ = 15

∴ Probability that both letters are vowels = 15/78 = 5/26.