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Find the equation of circle with centre  ( 3, 2) and radius 7 units. 
1. x2+ y2- 6x- 4y+ 36 = 0
2. x2+ y2- 6x- 4y- 36 = 0
3. x2+ y2+6x- 4y- 36 = 0
4. x2+ y2+ 6x+ 4y+ 36 = 0

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Correct Answer - Option 2 : x2+ y2- 6x- 4y- 36 = 0

Concept: 

Equation of circle having centre (h, k) and radius r is 

 (x – h) 2 + (y – k) 2 = r 

Calculation: 

Given, centre of circle ( 3, 2) and radius 7 units

We know that , equation of circle is  (x – h) 2 + (y – k) 2 = r  

According to the question, the equation of circle is 

( x - 3 )2 + ( y - 2 )2 = 72 

⇒ x2+ 9 - 6x + y2+ 4 - 4y = 49 

x2 + y2- 6x - 4y - 36 = 0. 

 The correct option is 2. 

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