Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
85 views
in Calculus by (114k points)
closed by
The equation of tangent to the curve y = x2 + 4x + 1 at (-1, - 2) is 
1. 2x - y = 0
2. 2x + y - 5 = 0
3. 2x - y - 1 = 0
4. x + y - 1 = 0
5. None of these

1 Answer

0 votes
by (115k points)
selected by
 
Best answer
Correct Answer - Option 1 : 2x - y = 0

Concept:

To determine the equation of a tangent to a curve:

Step. 1) Find the derivative of given curve 

Step. 2) Calculate the gradient of the tangent at given point.

Step. 3)  Determine the equation of tangent.

Substitute the gradient of the tangent and the coordinates of the given point into the gradient-point form of the straight line equation \(\rm (y - y_1) = m (x - x_1)\).

Calculations:

Given equation of curve is y = x2 + 4x + 1.

tep. 1) Find the derivative of given curve

Differentiate w.r.to x on both side, we get

\(\rm\dfrac{dy}{dx}= m = 2x + 4\)

Step. 2) Calculate the gradient of the tangent at given point

To determine the gradient of the tangent at the point (-1, -2), put x  = -1 into the equation for the derivative.
⇒ m =2 (- 1) + 4 

⇒ m = 2 

Step. 3)  Determine the equation of tangent.

Substitute the gradient of the tangent and the coordinates of the given point into the gradient-point form of the straight line equation.

\(\rm (y - y_1) = m (x - x_1)\)

⇒ (y +2) = 2(x+ 1)

⇒ 2x - y = 0

Hence, the equation of tangent to the curve y = x2 + 4x + 1 at (-1, -2) is  2x - y = 0

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...