Correct Answer - Option 2 : 3x - y - 2 = 0
Concept:
The equation of the tangent to a curve y = f(x) at a point (a, b) is given by (y - b) = m(x - a), where m = y'(b) = f'(a) [value of the derivative at point (a, b)].
Calculation:
y = f(x) = x3
⇒ y' = f'(x) = 3x2
m = f'(1) = 3 × 12 = 3
Equation of the tangent at (1, 1) will be:
(y - b) = m(x - a)
⇒ (y - 1) = 3(x - 1)
⇒ y - 1 = 3x - 3
⇒ 3x - y - 2 = 0.