Correct Answer - Option 4 : 16 years
Given∶
A certain sum of money compound interest which doubles itself in 4 years
Formula Used∶
A = P (1 + R/100)n
Calculation∶
Let the principal be Rs. P and rate f interest be R% p.a.
As the money doubles itself in 4 years, we have
2P = P (1 + R/100)4
⇒ (1 + R/100)4= 2P/P = 2
⇒ 1 +R/100 = 21/4
Let the money becomes 16 times in n years, then
16 P= P(1 + r/100)n
⇒ (1 + R/100)n = 16P/P = 16
⇒ (1 + R/100)n = (2)4
⇒ (21/4)n = 24
⇒ n/4 = 4
⇒ n = 16
∴ The required time period is 16 years.