LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
46 views
in General by (54.3k points)
closed by
The shearing stress in a piece of structural steel is 100 MPa. If the elastic modulus is 200 GPa and the Poisson’s ratio is 0.25, then the shearing strain 'γ'  would be
1. 0.00125 rad 
2. 0.8 rad 
3. 1.25 
4. 800

1 Answer

0 votes
by (30.0k points)
selected by
 
Best answer
Correct Answer - Option 1 : 0.00125 rad 

Explanation

Given: -

Shearing stress, τ = 100 MPa

Modulus of elasticity, E = 200 GPa

Poisson’s ratio, μ = 0.25

We know,

Modulus of rigidity (G) is defined as the ratio of shearing stress to the shearing strain.

Also,

\( \Rightarrow G = \frac{{200}}{{2\left( {1 + 0.25} \right)}} = 80\;GPa\)

Then,
\(G = \frac{\tau }{\gamma }\)

\( \Rightarrow \gamma = \frac{{100}}{{80 \times {{10}^3}}} = 0.00125\;rad\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...