Correct Answer - Option 1 : 0.00125 rad

**Explanation**

__Given__**: - **

Shearing stress, τ = 100 MPa

Modulus of elasticity, E = 200 GPa

Poisson’s ratio, μ = 0.25

We know,

Modulus of rigidity (G) is defined as the ratio of shearing stress to the shearing strain.

Also,

\( \Rightarrow G = \frac{{200}}{{2\left( {1 + 0.25} \right)}} = 80\;GPa\)

Then,

\(G = \frac{\tau }{\gamma }\)

\( \Rightarrow \gamma = \frac{{100}}{{80 \times {{10}^3}}} = 0.00125\;rad\)