Correct Answer - Option 1 : 0.00125 rad
Explanation
Given: -
Shearing stress, τ = 100 MPa
Modulus of elasticity, E = 200 GPa
Poisson’s ratio, μ = 0.25
We know,
Modulus of rigidity (G) is defined as the ratio of shearing stress to the shearing strain.
Also,
\( \Rightarrow G = \frac{{200}}{{2\left( {1 + 0.25} \right)}} = 80\;GPa\)
Then,
\(G = \frac{\tau }{\gamma }\)
\( \Rightarrow \gamma = \frac{{100}}{{80 \times {{10}^3}}} = 0.00125\;rad\)