Correct Answer - Option 4 : cot x
Concept:
Chain rule: \(\rm \frac{d}{dx}[f(g(x))]= f'(g(x)) g'(x)\)
If y = log x, then f'(x) = 1/x
And if y = sin x, then f'(x) = cos x
Calculation:
f(x) = log (sin x)
Differentiating with respect to x, we get
⇒ f'(x) = (\(\rm \frac{1}{sin\ x}\))\(\rm \frac{d \sin \ x\ }{dx}\)
⇒ f'(x) = \(\rm \frac{cos \ x}{sin \ x}\)
⇒ f'(x) = cot x