Correct Answer - Option 3 :
\(\rm \frac{2}{x}\)
Concept:
Chain rule: \(\rm \frac{d}{dx}[f(g(x))]= f'(g(x)) g'(x)\)
If y = log x, then f'(x) = 1/x
And if y = xn, then f'(x) = nxn - 1
Calculation:
f(x) = log x2, x > 1
Differentiating with respect to x, we get
⇒ f'(x) = (\(\rm \frac{1}{x^2}\))\(\rm \frac{d x^2}{dx}\)
⇒ f'(x) = \(\rm \frac{2x}{x^2}\)
⇒ f'(x) = \(\rm \frac{2}{x}\)