Correct Answer - Option 2 : 3 days
Given:
A can do the work in 4 days
B can do the work in 6 days
Concept used:
Total work = Efficiency × Time period
Calculation:
Taking the L.C.M of 4 & 6
L.C.M of 4 & 6 = 12
⇒ One day work of A = 12/4 = 3
⇒ One day work of B = 12/6 = 2
Work completed by B in one day = 2
⇒ Remaining work = 12 – 2 = 10
⇒ Time A and B take to complete the remaining work = 10/(3 + 2) = 10/5 = 2
⇒ Total number of days to complete the work = 1 + 2 = 3
∴ The number of days in which work is completed is 3 days.