Correct Answer - Option 2 :
\(\rm \left[ \begin{array}{cc} 3&-17\\-11&9\end{array} \right]\)
Concept:
The transpose of a matrix is simply a flipped version of the original matrix. We can get transpose by switching its rows with its columns. it is denoted by AT.
Calculation:
Given: \(\rm A = \left[ \begin{array}{cc} 1&-5\\-3&7\end{array} \right]\) and \(\rm B = \left[ \begin{array}{cc} 8&4\\1&3\end{array} \right]\)
AB = \(\rm \left[ \begin{array}{cc} 1&-5\\-3&7\end{array} \right]\)\(\rm \left[ \begin{array}{cc} 8&4\\1&3\end{array} \right]\)
⇒ \(\rm \left[ \begin{array}{cc} (1\times8)+(-5\times1)&(1\times4)+(-5\times3)\\(-3\times8)+(7\times1)&(-3\times4)+(7\times3)\end{array} \right]\)
⇒ \(\rm \left[ \begin{array}{cc} 3&-11\\-17&9\end{array} \right]\)
Now, we can get transpose of AB by switching its rows with its columns.
∴ (AB)T = \(\rm \left[ \begin{array}{cc} 3&-17\\-11&9\end{array} \right]\)
Hence, option (2) is correct.