Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
178 views
in General by (113k points)
closed by
What will be the circulation around rectangle defined by x = 0, y = 0, x = 1, y = 1 for a velocity field u = x and v = x + y ?
1. Infinity
2. 0 
3. 1 
4. 4

1 Answer

0 votes
by (114k points)
selected by
 
Best answer
Correct Answer - Option 3 : 1 

Concept:

Circulation = Vorticity × Area

where, 

Vorticity is defined as the value twice of the rotation.

ζ = 2ω

Rotation (ω) =  \({\omega _z} = \frac{1}{2}\left( {\frac{{∂ v}}{{∂ x}} - \frac{{∂ u}}{{∂ y}}} \right)\)

Now,

∴ Vorticity = \(\zeta = \frac{{∂ v}}{{∂ x}} - \frac{{∂ u}}{{∂ y}} \)

Calculation:

Given,

Velocity field, u = x, v = x + y

∴  ∂u/∂y = 0, ∂v/∂x = 1

Rectangular Field x = 0, y = 0, x = 1, y = 1 ( i.e Dimension of rectangular are 1 × 1 )

 Area of Recatangle = 1 × 1 = 1

Circulation = Vorticity × Area

\(Circulation= \left( {\frac{{∂ v}}{{∂ x}} - \frac{{∂ u}}{{∂ y}}} \right) × Area\)

Circulation= (1 – 0) × 1

∴ Circulation= 1 units

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...