Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
179 views
in Probability by (113k points)
closed by
Suppose a unbiased die is thrown 72 times and getting a 4 on a throw is termed as success then find the variance of number of success ?
1. 30
2. 5
3. 10
4. 20

1 Answer

0 votes
by (114k points)
selected by
 
Best answer
Correct Answer - Option 3 : 10

Concept:

Binomial distribution:

If a random variable X has binomial distribution as B (n, p) with n and p as parameters, then the probability of random variable is given as:

P( X = k) = nCpk q(n - k) where q = p - 1, n is the number of observations, p is the probability of success & q is the probability of failure

Note: The mean of a binomial distribution is np and variance is npq.

Calculation:

Given: An unbiased die is thrown 72 times and getting a 4 on a throw is termed as success

As we know that when a die is thrown there are 6 outcomes.

Let the probability of getting 4 on a throw which is termed as success is denoted by p.

⇒ p = 1/6

Let the probability of failure is denoted by q = 1 - p.

⇒ q = 1 -  1/6 = 5/6

As we know that, variance of a binomial distribution = npq

\(\rm ⇒variance = 72 \times \frac{1}{6} \times \frac{5}{6}=10\)

Hence, the correct option is 3.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...