Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
214 views
in Mathematics by (113k points)
closed by
The slope of the line perpendicular to the line passing through the points (3, 2) and (1, -1) is:
1. \(-2\over3\)
2. \(2\over3\)
3. \(3\over2\)
4. \(-3\over2\)

1 Answer

0 votes
by (114k points)
selected by
 
Best answer
Correct Answer - Option 1 : \(-2\over3\)

Concept:

The general equation of a line is y = mx + c 

Where m is the slope and c is any constant

  • The slope of parallel lines is equal.
  • Slope of the perpendicular line have their product = -1
 

Equation of a line passing through (x1, y1) and (x2, y2) is:

\(\rm {y-y_1\over x-x_1}={y_2-y_1\over x_2-x_1}\)

 

Calculation:

The line passing through the points (3, 2) and (1, -1)

The equation of the line is

\(\rm {y-2\over x-3}={-1-2\over1-3}\)

3x - 2y - 5 = 0

y = \(3\over2\)x - \(5\over2\)

⇒ Slope(m1) = \(3\over2\) and c1 = \(-5\over2\)

Now for the slope of the perpendicular line (m2)

m1 × m2 = -1

⇒ \(3\over2\) × m2 = -1 

⇒ m2 = \(-2\over3\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...