# If the probability that a student passes in JEE mains exam is 3/5. What will be the probability that out of 10 students, 6 students fails to pass the

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If the probability that a student passes in JEE mains exam is 3/5. What will be the probability that out of 10 students, 6 students fails to pass the JEE mains exam?

1. 10C6$\rm (\frac{2}{5})^{8}(\frac{3}{5})^{2}$
2. 10C6$\rm (\frac{2}{5})^{6}(\frac{3}{5})^{4}$
3. 10C6$\rm (\frac{3}{5})^{6}(\frac{2}{5})^{4}$
4. 10C6$\rm (\frac{4}{5})^{6}(\frac{3}{5})^{4}$

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Correct Answer - Option 2 : 10C6$\rm (\frac{2}{5})^{6}(\frac{3}{5})^{4}$

Concept:

Binomial distribution:

If a random variable X has binomial distribution as B (n, p) with n and p as parameters, then the probability of random variable is given as:

P( X = k) = nCpk q(n - k) where q = p - 1, n is the number of observations, p is the probability of success & q is the probability of failure.

Note: The mean of a binomial distribution is np and variance is npq.

Calculation:

Given: The probability that a student passes in JEE mains exam is 3/5.

Here, we have to find the probability that out of 10 students, 6 students fails to pass the JEE mains exam

It implies that the probability of failure denoted by q is 3/5.

Let the probability of success is denoted by p.

⇒ p = 1 - q = 1 - 3/5 = 2/5.

Here, n = 10, k = 6, p = 2/5 and q = 3/5

As we know that, P( X = k) = nCpk (1 - p)(n - k)

⇒ P( X = 6) =  10C6$\rm (\frac{2}{5})^{6}(\frac{3}{5})^{4}$

Hence, the correct option is 2.