Correct Answer - Option 3 : 45 years
Given
A sum of money doubles itself in 15 years with compound interest
Formula used
1) Amount(A) = Principal(P) × [1 + r/100]n where r = rate of interest and n = time period
2) (am)n = am × n
Calculation
A sum of money doubles itself in 15 years
⇒ Amount = 2P
2P = P × (1 + r/100)15
⇒ 2 = (1 + r/100)15
On cubing both sides, we get
23 = [(1 + r/100)15]3
⇒ 8 = (1 + r/100)45
⇒ 8P = P × (1 + r/100)45
∴ The sum of money becomes 8 times in 45 years